1z1-071 Certification – Valid Exam Dumps Questions Study Guide! (Updated 323 Questions)
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The Oracle 1Z0-071 exam is designed for those professionals who have some level of experience in operating with Oracle SQL and PL/SQL technologies and want to improve their expertise to perform the job roles of a Database Administrator or a Developer.
NEW QUESTION # 22
Which two are true about self joins?
- A. They have no join condition.
- B. They are always equijoins.
- C. They can use INNER JOIN and LEFT JOIN.
- D. They require the EXISTS opnrator in the join condition.
- E. They require table aliases.
- F. They require the NOT EXISTS operator in the join condition.
Answer: C,E
Explanation:
Self joins in Oracle Database 12c SQL have these characteristics:
* Option D: They can use INNER JOIN and LEFT JOIN.
* Self joins can indeed use various join types, including inner and left outer joins. A self join is a regular join, but the table is joined with itself.
* Option E: They require table aliases.
* When a table is joined to itself, aliases are required to distinguish between the different instances of the same table within the same query.
Options A, B, C, and F are incorrect:
* Option A is incorrect because self joins can be non-equijoins as well.
* Option B is incorrect because self joins do not require the NOT EXISTS operator. They may require a condition, but NOT EXISTS is not a necessity.
* Option C is incorrect because a join condition is needed to relate the two instances of the same table in a self join.
* Option F is incorrect for the same reason as B; the EXISTS operator is not a requirement for self joins.
NEW QUESTION # 23
Examine the data in the ENPLOYEES table:
Which statement will compute the total annual compensation tor each employee?
- A. SELCECT last_namo, (monthly_salary * 12) + (monthly_commission_pct * 12) AS annual_comp FROM employees
- B. SELCECT last_namo, (monthly_salary * 12) + (menthy_salary * 12 * monthly_commission_pct) AS annual_comp FROM employees
- C. SECECT last_namo, (menthy_salary + monthly_commission_pct) * 12 AS annual_comp FROM employees;
- D. SELCECT last_namo, (monthly_salary * 12) + (menthy_salary * 12 * NVL (monthly_commission_pct, 0)) AS annual_comp FROM employees
Answer: D
NEW QUESTION # 24
Which two statements are true about the data dictionary?
- A. Views with the prefix all_ display metadata for objects to which the current user has access.
- B. Views with the prefix all_, dba_ and useb_ are not all available for every type of metadata.
- C. The data dictionary is accessible when the database is closed.
- D. The data dictionary does not store metadata in tables.
- E. Views with the prefix dba_ display only metadata for objects in the SYS schema.
Answer: A,B
NEW QUESTION # 25
Which three are true about the CREATE TABLE command?
- A. It implicitly executes a commit.
- B. The owner of the table must have the UNLIMITED TABLESPACE system privilege.
- C. It can include the CREATE...INDEX statement for creating an index to enforce the primary key constraint.
- D. A user must have the CREATE ANY TABLE privilege to create tables.
- E. It implicitly rolls back any pending transactions.
- F. The owner of the table should have space quota available on the tablespace where the table is defined.
Answer: A,D,F
Explanation:
A). False - The CREATE TABLE command cannot include a CREATE INDEX statement within it. Indexes to enforce constraints like primary keys are generally created automatically when the constraint is defined, or they must be created separately using the CREATE INDEX command.
B). True - The owner of the table needs to have enough space quota on the tablespace where the table is going to be created, unless they have the UNLIMITED TABLESPACE privilege. This ensures that the database can allocate the necessary space for the table. Reference: Oracle Database SQL Language Reference, 12c Release 1 (12.1).
C). True - The CREATE TABLE command implicitly commits the current transaction before it executes. This behavior ensures that table creation does not interfere with transactional consistency. Reference: Oracle Database SQL Language Reference, 12c Release 1 (12.1).
D). False - It does not implicitly roll back any pending transactions; rather, it commits them.
E). True - A user must have the CREATE ANY TABLE privilege to create tables in any schema other than their own. To create tables in their own schema, they need the CREATE TABLE privilege. Reference: Oracle Database Security Guide, 12c Release 1 (12.1).
F). False - While the UNLIMITED TABLESPACE privilege allows storing data without quota restrictions on any tablespace, it is not a mandatory requirement for a table owner. Owners can create tables as long as they have sufficient quotas on the specific tablespaces.
NEW QUESTION # 26
which three statements are true about indexes and their administration in an Oracle database?
- A. A DESCENDING INDEX IS A type of function-based index
- B. AN INVISIBLE INDEX is not maintained when DML is performed on its underlying table.
- C. A DROP INDEX statement always prevents updates to the table during the drop operation
- D. AN INDEX CAN BE CREATED AS part of a CREATE TABLE statement
- E. IF a query filters on an indexed column then it will always be used during execution of query
- F. The same table column can be part of a unique and non-unique index
Answer: A,C,D
NEW QUESTION # 27
The sales table has columns prod_id and quantity_sold of data type number. Which two queries execute successfully?
- A. SELECT prod_id FROM sales WHERE quantity_sold > 55000 AND
COUNT(*) > 10 GROUP BY COUNT(*) > 10; - B. SELECT prod_id FROM sales WHERE quantity_sold > 55000 AND COUNT(*) > 10 GROUP BY prod_id HAVING COUNT(*) > 10;
- C. SELECT COUNT(prod_id) FROM sales WHERE quantity_sold > 55000 GROUP BY prod_id;
- D. SELECT prod Id FROH sales NHERE quantity sold > 55000 3RODI BY prod_id HAVING COUNT(*)
> 10; - E. SELECT COUNT(prod_id) FROM sales GROUP BY prod_id WHERE quantity_sold > 55000;
Answer: C,D
NEW QUESTION # 28
View the Exhibit and examine the structure of CUSTOMERStable.
Using the CUSTOMERStable, you need to generate a report that shows an increase in the credit limit by
15% for all customers. Customers whose credit limit has not been entered should have the message "Not Available" displayed.
Which SQL statement would produce the required result?
- A. SELECT NVL(cust_credit_limit), 'Not Available') "NEW CREDIT"
FROM customers; - B. SELECT TO_CHAR (NVL(cust_credit_limit * .15), 'Not Available') "NEW CREDIT" FROM customers;
- C. SELECT NVL(cust_credit_limit * .15), 'Not Available') "NEW CREDIT"
FROM customers; - D. SELECT NVL (TO CHAR(cust_credit_limit * .15), 'Not Available') "NEW CREDIT" FROM customers;
Answer: D
NEW QUESTION # 29
Examine this query which executes successfully;
Select job,deptno from emp
Union all
Select job,deptno from jobs_history;
What will be the result?
- A. It will return rows from both select statements after eliminating duplicate rows.
- B. It will return rows common to both select statements.
- C. It will return rows both select statements including duplicate rows.
- D. It will return rows that are not common to both select statements.
Answer: C
Explanation:
For the provided UNION ALL query:
* Option C: It will return rows from both SELECT statements including duplicate rows.
* UNION ALL is used to combine the results of two SELECT statements and does not eliminate duplicates.
Options A, B, and D are incorrect because:
* Option A: UNION ALL does not eliminate duplicate rows, unlike UNION.
* Option B: This would be true for INTERSECT, not UNION ALL.
* Option D: This would be true for EXCEPT or MINUS, not UNION ALL.
NEW QUESTION # 30
You are designing the structure of a table in which two columns have the specifications:
COMPONENT_ID - must be able to contain a maximum of 12 alphanumeric characters and must uniquely identify the row
EXECUTION_DATETIME - contains Century, Year, Month, Day, Hour, Minute, Second to the maximum precision and is used for calculations and comparisons between components.
Which two options define the data types that satisfy these requirements most efficiently? (Choose two.)
- A. The COMPONENT_ID must be of ROWID data type.
- B. The EXECUTION_DATETIME must be of DATE data type.
- C. The COMPONENT_ID must be of VARCHAR2 data type.
- D. The COMPONENT_ID column must be of CHAR data type.
- E. The EXECUTION_DATETIME must be of TIMESTAMP data type.
- F. The EXECUTION_DATETIME must be of INTERVAL DAY TO SECOND data type.
Answer: B,D
NEW QUESTION # 31
View the Exhibit and examine the structure of the ORDERS table. The ORDER_ID column is the PRIMARY KEY in the ORDERS table.
Evaluate the following CREATE TABLE command:
CREATE TABLE new_orders(ord_id, ord_date DEFAULT SYSDATE, cus_id)
AS
SELECT order_id.order_date,customer_id
FROM orders;
Which statement is true regarding the above command?
- A. The NEW_ODRDERS table would get created and all the constraints defined on the specified columns in the ORDERS table would be passed to the new table.
- B. The NEW_ODRDERS table would not get created because the DEFAULT value cannot be specified in the column definition.
- C. The NEW_ODRDERS table would not get created because the column names in the CREATE TABLE command and the SELECT clause do not match.
- D. The NEW_ODRDERS table would get created and only the NOT NULL constraint defined on the specified columns would be passed to the new table.
Answer: D
NEW QUESTION # 32
Which two statements are true about a full outer join?
- A. It includes rows that are returned by an inner join.
- B. The Oracle join operator (+) must be used on both sides of the join condition in the WHERE clause.
- C. It returns only unmatched rows from both tables being joined.
- D. It returns matched and unmatched rows from both tables being joined.
- E. It includes rows that are returned by a Cartesian product.
Answer: A,D
Explanation:
In Oracle Database 12c, regarding a full outer join:
* A. It includes rows that are returned by an inner join. This is true. A full outer join includes all rows from both joined tables, matching wherever possible. When there's a match in both tables (as with an inner join), these rows are included.
* D. It returns matched and unmatched rows from both tables being joined. This is correct and the essence of a full outer join. It combines the results of both left and right outer joins, showing all rows from both tables with matching rows from the opposite table where available.
Options B, C, and E are incorrect:
* B is incorrect because the Oracle join operator (+) is used for syntax in older versions and cannot implement a full outer join by using (+) on both sides. Proper syntax uses the FULL OUTER JOIN keyword.
* C is incorrect as a Cartesian product is the result of a cross join, not a full outer join.
* E is incorrect because it only describes the scenario of a full anti-join, not a full outer join.
NEW QUESTION # 33
Examine the structure of the ORDERS table:
You want to find the total value of all the orders for each year and issue this command:
SQL> SELECT TO_CHAR(order_date,'rr'), SUM(order_total) FROM orders
GROUP BY TO_CHAR(order_date, 'yyyy');
Which statement is true regarding the result? (Choose the best answer.)
- A. It return an error because the datatype conversion in the SELECT list does not match the data type conversion in the GROUP BY clause.
- B. It executes successfully but does not give the correct output.
- C. It returns an error because the TO_CHAR function is not valid.
- D. It executes successfully and gives the correct output.
Answer: A
NEW QUESTION # 34
View the Exhibit and examine the structure of the CUSTOMERS table.
You want to generate a report showing the last names and credit limits of all customers whose last names start with A, B, or C, and credit limit is below 10,000.
Evaluate the following two queries:
SQL> SELECT cust_last_name, cust_credit_limit FROM customers
WHERE (UPPER(cust_last_name) LIKE 'A%' OR
UPPER (cust_last_name) LIKE 'B%' OR UPPER (cust_last_name) LIKE 'C%')
AND cust_credit_limit < 10000;
SQL>SELECT cust_last_name, cust_credit_limit FROM customers
WHERE UPPER (cust_last_name) BETWEEN 'A' AND 'C'
AND cust_credit_limit < 10000;
Which statement is true regarding the execution of the above queries?
- A. Both execute successfully but do not give the required result
- B. Only the first query gives the correct result
- C. Only the second query gives the correct result
- D. Both execute successfully and give the same result
Answer: B
NEW QUESTION # 35
View the Exhibit and examine the structure of the PROMOTIONS table.
Evaluate the following SQL statement:
Which statement is true regarding the outcome of the above query?
- A. It shows COST_REMARKfor all the promos in the promo category 'TV'.
- B. It shows COST_REMARKfor all the promos in the table.
- C. It produces an error because subqueries cannot be used with the CASEexpression.
- D. It produces an error because the subquery gives an error.
Answer: B
NEW QUESTION # 36
Examine these SQL statements which execute successfully:
Which two statements are true after execution?
- A. The foreign key constraint will be disabled.
- B. The foreign key constraint will be enabled and IMMEDIATE.
- C. The foreign key constraint will be enabled and DEFERRED.
- D. The primary key constraint will be enabled and DEFERRED.
- E. The primary key constraint will be enabled and IMMEDIATE.
Answer: B,D
NEW QUESTION # 37
Examine the description of the EMPLOYEES table:
Which two statements will run successfully?
- A. SELECT 'The first_name is '|| first_name|| '' FROM employees;
- B. SELECT 'The first_name is \'' || first_name || '\'' FROM employees;
- C. SELECT 'The first_name is '''||first_name ||'''' FROM employees ;
- D. SELECT 'The first_name is '' || first_name || '' FROM employees ;
- E. SELECT 'The first_name is ''' ||first_name||''' FROM employees ;
Answer: A,C
NEW QUESTION # 38
Which three statements are true about the Oracle join and ANSI Join syntax?
- A. The SQL:1999 compliant ANSI join syntax supports creation of a Cartesian product of two tables.
- B. The SQL:1999 compliant ANSI join syntax supports natural joins.
- C. The Oracle join syntax performs better than the SQL:1999 compliant ANSI join syntax.
- D. The Oracle join syntax only supports right outer joins,
- E. The Oracle join syntax supports creation of a Cartesian product of two tables.
- F. The Oracle join syntax supports natural joins.
- G. The Oracle join syntax performs less well than the SQL:1999 compliant ANSI Join Answer.
Answer: A,B,E
Explanation:
Regarding Oracle join and ANSI join syntax:
* B. The Oracle join syntax supports the creation of a Cartesian product of two tables. This is true.
In Oracle, if you list tables in the FROM clause without a join condition, it creates a Cartesian product.
* C. The SQL:1999 compliant ANSI join syntax supports natural joins. This is true. ANSI syntax supports natural joins, which join tables based on columns with the same names in the joined tables.
* F. The SQL:1999 compliant ANSI join syntax supports the creation of a Cartesian product of two tables. This is true. The ANSI standard allows for Cartesian products when tables are listed in the FROM clause without a join condition.
Options A, D, E, and G are incorrect:
* A is incorrect because the Oracle join syntax supports all types of joins, including right outer joins.
* D is incorrect because Oracle's proprietary join syntax does not use the term "natural join."
* E is incorrect because there is no inherent performance difference between Oracle join syntax and ANSI join syntax; performance depends on how the query is written and how the database optimizer handles it.
* G is incorrect for the same reason as E.
NEW QUESTION # 39
Which two are true about the USING clause when joining tables?
- A. It is used to specify an explicit join condition involving operators.
- B. It is used to specify an equijoin of columns that have the same name in both tables.
- C. All column names in a USING clause must be qualified with a table name or table alias.
- D. It can never be used with onatural join.
- E. It can never be used with a full outer join.
Answer: B,E
Explanation:
When joining tables in Oracle Database 12c, the USING clause has specific behaviors:
* Option C: It is used to specify an equijoin of columns that have the same name in both tables.
* The USING clause is indeed used to specify an equijoin between two tables based on columns with identical names in the tables being joined. It simplifies the syntax of the JOIN operation by eliminating the need to qualify the joined columns with table names.
* Option D: It can never be used with a full outer join.
* The USING clause cannot be used with a full outer join because the full outer join requires a specification of how to treat each side of the join, including rows that don't match the join condition, which is not compatible with the semantics of the USING clause.
Options A, B, and E are incorrect:
* Option A is incorrect because when using the USING clause, you do not need to qualify the columns with table names or aliases in the select list; Oracle assumes that they are the same in both tables.
* Option B is incorrect because the USING clause can be used with natural joins.
* Option E is incorrect as the USING clause is not meant to specify explicit join conditions with operators; it's specifically for equijoins on columns of the same name.
NEW QUESTION # 40
Examine this statement:
SELECT1 AS id,' John' AS first_name, NULL AS commission FROM dual
INTERSECT
SELECT 1,'John' null FROM dual ORDER BY 3;
What is returned upon execution?[
- A. An error
- B. 2 rows
- C. 0 rows
- D. 1 ROW
Answer: D
NEW QUESTION # 41
View the Exhibit and examine the structure of the PRODUCTS table.
You must display the category with the maximum number of items.
You issue this query:
What is the result?
- A. It executes successfully but does not give the correct output.
- B. It generates an error because = is not valid and should be replaced by the IN operator.
- C. It executes successfully and gives the correct output.
- D. It generate an error because the subquery does not have a GROUP BY clause.
Answer: D
NEW QUESTION # 42
Which two statements are true about date/time functions in a session where NLS_DATE_PORMAT is set to DD-MON-YYYY SH24:MI:SS
- A. CURRENT_TIMESTAMP returns the same date and time as SYSDATE with additional details of functional seconds.
- B. SYSDATE can be used in expressions only if the default date format is DD-MON-RR.
- C. SYSDATE and CURRENT_DATE return the current date and time set for the operating system of the database server.
- D. SYSDATE can be queried only from the DUAL table.
- E. CURRENT_DATE returns the current date and time as per the session time zone
- F. CURRENT_TIMESTAMP returns the same date as CURRENT_DATE.
Answer: C,E
Explanation:
In Oracle Database 12c SQL, regarding date/time functions and considering a session where NLS_DATE_FORMAT is set to DD-MON-YYYY SH24:MI:SS:
* C. CURRENT_DATE returns the current date and time as per the session time zone. This is correct as CURRENT_DATE returns the current date and time in the time zone of the current SQL session, as set by the ALTER SESSION command.
* D. SYSDATE and CURRENT_DATE return the current date and time set for the operating system of the database server. This is partially correct. SYSDATE returns the current date and time from the operating system of the database server. However, CURRENT_DATE returns the date and time set for the client's operating system environment, adjusted to the session time zone.
Options A, B, E, and F are incorrect based on Oracle's documentation:
* A is incorrect because SYSDATE is independent of the NLS_DATE_FORMAT setting.
* B is incorrect because CURRENT_TIMESTAMP includes time zone information, which can differ from CURRENT_DATE.
* E is incorrect because CURRENT_TIMESTAMP differs from SYSDATE by including fractional seconds and time zone.
* F is incorrect as SYSDATE can be queried in any SELECT statement, not just from DUAL.
NEW QUESTION # 43
An Oracle database server session has an uncommitted transaction in progress which updated 5000 rows in a table.
In which three situations does the transact ion complete thereby committing the updates?
- A. When a DBA issues a successful SHUTDOWN TRANSACTIONAL statement and the user, then issues a COMMIT
- B. When a COMMIT statement is issued by the same user from another session in the same database instance
- C. When the session logs out is successfully
- D. When a CREATE INDEX statement is executed successfully in same session
- E. When a CREATE TABLE AS SELECT statement is executed unsuccessfully in the same session
- F. When a DBA issues a successful SHUTDOWN IMMEDIATE statement and the user then issues a COMMIT
Answer: A,C,D
Explanation:
For situations where the transaction would complete by committing the updates:
* A. When the session logs out successfully: When a user session logs out, Oracle automatically commits any outstanding transactions.
* C. When a CREATE INDEX statement is executed successfully in the same session: Most DDL statements, including CREATE INDEX, cause an implicit commit before and after they are executed.
* F. When a DBA issues a successful SHUTDOWN TRANSACTIONAL statement: This type of shutdown ensures that active transactions are either committed or rolled back. If a COMMIT is then issued explicitly, it would be redundant but emphasizes the transaction completion.
Incorrect options:
* B: SHUTDOWN IMMEDIATE will roll back transactions, not commit them.
* D: A COMMIT in one session cannot affect the transaction state of another session; each session is isolated in terms of transaction management.
* E: If a CREATE TABLE AS SELECT statement executes unsuccessfully, no implicit commit is performed; the statement failure means the transaction state remains unchanged.
NEW QUESTION # 44
Evaluate the following SQL statement
SQL>SELECT promo_id, prom _category FROM promotions
WHERE promo_category='Internet' ORDER BY promo_id
UNION
SELECT promo_id, promo_category FROM Pomotions
WHERE promo_category = 'TV'
UNION
SELECT promoid, promocategory FROM promotions WHERE promo category='Radio' Which statement is true regarding the outcome of the above query?
- A. It produces an error because positional, notation cannot be used in the ORDER BY clause with SBT operators.
- B. It produces an error because the ORDER BY clause should appear only at the end of a compound query-that is, with the last SELECT statement.
- C. It executes successfully and displays rows in the descend ignore of PROMO CATEGORY.
- D. It executes successfully but ignores the ORDER BY clause because it is not located at the end of the compound statement.
Answer: B
NEW QUESTION # 45
View the exhibit and examine the structure of the PROMOTIONS table.
You have to generate a report that displays the promo name and start date for all promos that started after the last promo in the 'INTERNET' category.
Which query would give you the required output?
- A. SELECT promo_name, promo_begin_date FROM promotionsWHERE
promo_begin_date> ALL (SELECT MAX (promo_begin_date)FROM promotions)
ANDpromo_category= 'INTERNET'; - B. SELECT promo_name, promo_begin_date FROM promotionsWHERE
promo_begin_date IN (SELECT promo_begin_dateFROM promotionsWHERE
promo_category= 'INTERNET'); - C. SELECT promo_name, promo_begin_date FROM promotionsWHERE
promo_begin_date> ANY (SELECT promo_begin_dateFROM promotionsWHERE
promo_category= 'INTERNET'); - D. SELECT promo_name, promo_begin_date FROM promotionsWHERE
promo_begin_date > ALL (SELECT promo_begin_dateFROM promotionsWHERE
promo_category = 'INTERNET');
Answer: D
NEW QUESTION # 46
Examine the business rule:
Each student can work on multiple projects and each project can have multiple students.
You need to design an Entity Relationship Model (ERD) for optimal data storage and allow for generating reports in this format:
STUDENT_ID FIRST_NAME LAST_NAME PROJECT_ID PROJECT_NAME
PROJECT_TASK
Which two statements are true in this scenario?
- A. STUDENT_ID must be the primary key in the STUDENTS entity and foreign key in the PROJECTS entity.
- B. The ERD must have a M:M relationship between the STUDENTS and PROJECTS entities that must be resolved into 1:M relationships.
- C. PROJECT_ID must be the primary key in the PROJECTS entity and foreign key in the STUDENTS entity.
- D. An associative table must be created with a composite key of STUDENT_ID and PROJECT_ID, which is the foreign key linked to the STUDENTS and PROJECTS entities.
- E. The ERD must have a 1:M relationship between the STUDENTS and PROJECTS entities.
Answer: B,D
Explanation:
References:
http://www.oracle.com/technetwork/issue-archive/2011/11-nov/o61sql-512018.html
NEW QUESTION # 47
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